Question

For the function f:x maps to 4x-x^3 determine:
a. the coordinates of the stationary points
b. the nature of each of the stationary points

Answer 1

sure

Answer 2

yep!

Answer 3

f(x)=4x-x^3
dy/dx=4-3x^2

Answer 4

solve for when dy/dx=0

Answer 5

from there what do i do because i can't get the coordinates

Answer 6

hence, x^2=SR4/3

Answer 7

when y=0 of course

Answer 8

well, y intercept (c) is 4 right?

Answer 9

so co-ords are (0,4)

Answer 10

that's the maxima, stationary

Answer 11

funny thing is, i'm revising for this topic too

Answer 12

when you asked the question lol

Answer 13

where are you from?

Answer 14

cool but i still stuck here at the point when i get dy/dx=4-3^2

Answer 15

im from Jamaica u?

Answer 16

ooh cool! I live in Hong Kong

Answer 17

how do u know that dy/dx=0

Answer 18

\[f(x)=4x-x^3\]
\[dy/dx=-3x^2+4=0\]

Answer 19

what's dy/dx? it's the gradient right? so when it's at maxima or minima, gradient is always 0

Answer 20

and since this is a negative quadratic graph, it's maxima