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If f(x) = 12x + 7, what is f–1(x)?
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Do you mean f(-1)?
\[f^{-1}(x)\]
lolol
=(x-7)/12
-f(x) maybe :P
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lmao f(x)^-1 :P
or is that a negative prime? :o
= \[\LARGE {1 \over 12x + 7}\]
I'm not sure if right. If wrong, please correct me.
icky
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that's wrong because the question is ambiguous
Okay
inverse?
ask coconut to set it up properly
coconut is a coconut :P
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@Tai please don't speak of members like this. She/he will do it.
\[ f^{1} (x)\]i meant
@ParthKohli OK
12
dy/dx = 12
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medal please
12x^1 +7(x^0) --> 12 + 0
f'(x) = 12
medal please, one for me one for you :D
My options are x - 12/7 x+12/7 x-7/12 x+7/12
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you haven't answered the question asked tai
\[f(x) = 12x + 7\]\[f(x)-7=12x\]\[\frac{f(x)-7}{12}=x\]\[\frac{x-7}{12}=f^{-1}(x)\]
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