Question

I figured out the min is DNE, but can't seem to get the maximum. Help! :)

Find the absolute maximum value and absolute minimum, if any, of the function:

Answer 1

see attachment image for problem.

Answer 2

how did you get -2 ?

Answer 3

used the second derivative test.. i think?

Answer 4

just need one derivative to find the max since you already know there is no min

Answer 5

It's a quadratic equation, so the absolute min/max will be at the x-coordinate\[x = \frac {-b}{2a}\]After you get your x-coordinate, plug that in for x into the equation to get the max.

Answer 6

^that would be the non-calculus approach
whichever you prefer

Answer 7

this is from my Business Calculus class.. ok i'll try the first derivative test.

Answer 8

First derivative comes out to -2x + 4.. where do I go from there?

How do I get the exact value of the maximum?

Answer 9

Set the first derivative equal to 0 and solve for x. That'll give you the x-coordinate of the maximum.

Answer 10

what about the y coordinate?

Answer 11

the system didn't accept maximum of .5 :(

Answer 12

From -2x + 4 = 0 you get that x = 2. So, y = 8, am I right?

Answer 13

pretty sure you are

Answer 14

how didyou get 0.5 LadyGem ?

Answer 15

first derivative test is -2x+4, solve for x= 1/2? move the -2x over to make it positive, then divide by 2 to get x alone. Did I miss something?

Answer 16

oh snap.. i'm an idiot. sorry, its 2

Answer 17

you're not an idiot, but it is 2 ;)

Answer 18

thanks lol.

ok so with x being 2, how did is y=8?

Answer 19

plug x=2 into the formula for y

Answer 20

or g(x) rather, whatever you want to call it

Answer 21

so it wants to know the value of g(2)

Answer 22

lol... duh.. i knew that too! ok got it now.. finally

Answer 23

no prob, happy to help :)