sr(x+4)=-3
x+4=(-3)^2 x+4=9 x=9-4 x=5
-3^2=9=(x+4) x=9-4=5
medal for you and me
u tell where u r facing problem...
whoa hold the phone
if this is \[\sqrt{x+4}=-3\] then there is no solution because the left hand side is positive and the right hand side is negative
how can you say LHS is positive...
he/she wrote "sr(x+4)" not sure precisely what is meant, but my guess is it means \[\sqrt{x+4}\] which is certainly positive
yeah sr means square root only but if we see sqrt4 den answer is 2 or -2.. so u cant say LHS is always positive...
\[\sqrt{4}=2\]
no its positive squareroot
Every positive number a has two square roots: , which is positive, and , which is negative. quote from wikipedia.... http://en.wikipedia.org/wiki/Square_root
x=5
yes of course every positive number has two square roots. if we call the number \(a\) then they are denoted by \(\sqrt{a}\) and \(-\sqrt{a}\)
so if you see \(\sqrt{x+4}\) you can be sure it is positive
what if we let x=0 then sqrt4=2 or(-2)
??
oh i see. if you let \(x=0\) you get \(\sqrt{0+4}=\sqrt{4}=2\)
2 and (-2) both because 2^2=4 also, (-2)^2=4
x=5. The End!
@morales its not baout answer... logic should b clear too..
about*
it is certainly true that \(x^2=4\) has two solutions. they are \(\sqrt{4}=2\) and \(-\sqrt{4}=-2\)
notice that \(\sqrt{4}\) means the positive solution , and therefore \(\sqrt{x+4}\geq 0\)
which is why the equation above has no solution
the radical sign is the principle square root... this is never negative.
Vedic solved the question. His logic is correct. Nothing else need be said. BTW, you can find the square root of any number positive or negative. I will leave to you geniuses to figure it out.
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