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Mathematics 11 Online
OpenStudy (anonymous):

sr(x+4)=-3

OpenStudy (anonymous):

x+4=(-3)^2 x+4=9 x=9-4 x=5

OpenStudy (anonymous):

-3^2=9=(x+4) x=9-4=5

OpenStudy (anonymous):

medal for you and me

OpenStudy (anonymous):

u tell where u r facing problem...

OpenStudy (anonymous):

whoa hold the phone

OpenStudy (anonymous):

if this is \[\sqrt{x+4}=-3\] then there is no solution because the left hand side is positive and the right hand side is negative

OpenStudy (anonymous):

how can you say LHS is positive...

OpenStudy (anonymous):

he/she wrote "sr(x+4)" not sure precisely what is meant, but my guess is it means \[\sqrt{x+4}\] which is certainly positive

OpenStudy (anonymous):

yeah sr means square root only but if we see sqrt4 den answer is 2 or -2.. so u cant say LHS is always positive...

OpenStudy (anonymous):

\[\sqrt{4}=2\]

OpenStudy (anonymous):

no its positive squareroot

OpenStudy (anonymous):

Every positive number a has two square roots: , which is positive, and , which is negative. quote from wikipedia.... http://en.wikipedia.org/wiki/Square_root

OpenStudy (anonymous):

x=5

OpenStudy (anonymous):

yes of course every positive number has two square roots. if we call the number \(a\) then they are denoted by \(\sqrt{a}\) and \(-\sqrt{a}\)

OpenStudy (anonymous):

so if you see \(\sqrt{x+4}\) you can be sure it is positive

OpenStudy (anonymous):

what if we let x=0 then sqrt4=2 or(-2)

OpenStudy (anonymous):

??

OpenStudy (anonymous):

oh i see. if you let \(x=0\) you get \(\sqrt{0+4}=\sqrt{4}=2\)

OpenStudy (anonymous):

2 and (-2) both because 2^2=4 also, (-2)^2=4

OpenStudy (anonymous):

x=5. The End!

OpenStudy (anonymous):

@morales its not baout answer... logic should b clear too..

OpenStudy (anonymous):

about*

OpenStudy (anonymous):

it is certainly true that \(x^2=4\) has two solutions. they are \(\sqrt{4}=2\) and \(-\sqrt{4}=-2\)

OpenStudy (anonymous):

notice that \(\sqrt{4}\) means the positive solution , and therefore \(\sqrt{x+4}\geq 0\)

OpenStudy (anonymous):

which is why the equation above has no solution

OpenStudy (anonymous):

the radical sign is the principle square root... this is never negative.

OpenStudy (anonymous):

Vedic solved the question. His logic is correct. Nothing else need be said. BTW, you can find the square root of any number positive or negative. I will leave to you geniuses to figure it out.

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