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Mathematics 14 Online
OpenStudy (anonymous):

need help

OpenStudy (anonymous):

on what?

OpenStudy (anonymous):

on what darling?

OpenStudy (anonymous):

oh wait you're older than me :o

OpenStudy (anonymous):

sorry madam! how may i be of your assistance?

OpenStudy (anonymous):

lol yea

OpenStudy (anonymous):

turning 22 on the 14th of may

OpenStudy (anonymous):

\[\left(\begin{matrix}2 \\ 7\end{matrix}\right)^{2}\times \left(\begin{matrix}7 \\11\end{matrix}\right)^{2}=\]

OpenStudy (anonymous):

4/49*49/121

OpenStudy (anonymous):

4/121 = 0.033 = 3%

OpenStudy (anonymous):

not matrices?

OpenStudy (anonymous):

phew...thought it was matrices lol

OpenStudy (anonymous):

oh wait... is that just fractions that your talking about right?

OpenStudy (turingtest):

\[(\frac72)^2\times(\frac7{11})^2\]?

OpenStudy (anonymous):

i thought it was matrices lol

OpenStudy (anonymous):

yes turningtest

OpenStudy (anonymous):

lol tai =P

OpenStudy (turingtest):

well, they are all prime numbers so nothing to be simplified so just square each number and multiply straight across

OpenStudy (turingtest):

wait, you had\[(\frac27)^2\times(\frac7{11})^2\]

OpenStudy (turingtest):

so in that case something will cancel...

OpenStudy (anonymous):

@Tai , I thought it was a Combination sum (Permutation and Combination) :P

OpenStudy (anonymous):

7

OpenStudy (turingtest):

so you are left with...?

OpenStudy (anonymous):

haha

OpenStudy (anonymous):

4/121

Parth (parthkohli):

\[\LARGE ({2 \over 7})^{2} * ({7 \over 11})^{2} = {4 \over \cancel {49}} * {\cancel{49} \over 121} = {4 \over 121}\]

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