Mathematics
14 Online
OpenStudy (anonymous):
need help
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OpenStudy (anonymous):
on what?
OpenStudy (anonymous):
on what darling?
OpenStudy (anonymous):
oh wait you're older than me :o
OpenStudy (anonymous):
sorry madam! how may i be of your assistance?
OpenStudy (anonymous):
lol yea
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OpenStudy (anonymous):
turning 22 on the 14th of may
OpenStudy (anonymous):
\[\left(\begin{matrix}2 \\ 7\end{matrix}\right)^{2}\times \left(\begin{matrix}7 \\11\end{matrix}\right)^{2}=\]
OpenStudy (anonymous):
4/49*49/121
OpenStudy (anonymous):
4/121 = 0.033 = 3%
OpenStudy (anonymous):
not matrices?
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OpenStudy (anonymous):
phew...thought it was matrices lol
OpenStudy (anonymous):
oh wait... is that just fractions that your talking about right?
OpenStudy (turingtest):
\[(\frac72)^2\times(\frac7{11})^2\]?
OpenStudy (anonymous):
i thought it was matrices lol
OpenStudy (anonymous):
yes turningtest
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OpenStudy (anonymous):
lol tai =P
OpenStudy (turingtest):
well, they are all prime numbers so nothing to be simplified
so just square each number and multiply straight across
OpenStudy (turingtest):
wait, you had\[(\frac27)^2\times(\frac7{11})^2\]
OpenStudy (turingtest):
so in that case something will cancel...
OpenStudy (anonymous):
@Tai , I thought it was a Combination sum (Permutation and Combination) :P
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OpenStudy (anonymous):
7
OpenStudy (turingtest):
so you are left with...?
OpenStudy (anonymous):
haha
OpenStudy (anonymous):
4/121
Parth (parthkohli):
\[\LARGE ({2 \over 7})^{2} * ({7 \over 11})^{2} = {4 \over \cancel {49}} * {\cancel{49} \over 121} = {4 \over 121}\]