The stopping distance s of a car varies directly as the square of its speed v. If a car traveling 30 mph requires 45 ft to stop, find the stopping distance for a car traveling 65 mph.

Question

anonymous · Answer

$$s=20(65)^2$$

radar · Answer

s=kv^2
45=k30^2
45=k900
k=45/900=1/20

s=(1/20)65^2
s=4225/20=211.25 ft.

anonymous · Answer

Thank You!!

radar · Answer

@ebbflo, is that your dog in the logo?

radar · Answer

I believe ebbflo meant (1/20)(65)^2

anonymous · Answer

no that's me:)

yeah it is one of my dogs

anonymous · Answer

yeah

anonymous · Answer

sorry

radar · Answer

Beautiful animal.  As you may see my logo has my dog, a boston terrier.