Question

The stopping distance s of a car varies directly as the square of its speed v. If a car traveling 30 mph requires 45 ft to stop, find the stopping distance for a car traveling 65 mph.

Answer 1

\[s=20(65)^2\]

Answer 2

s=kv^2
45=k30^2
45=k900
k=45/900=1/20

s=(1/20)65^2
s=4225/20=211.25 ft.

Answer 3

Thank You!!

Answer 4

@ebbflo, is that your dog in the logo?

Answer 5

I believe ebbflo meant (1/20)(65)^2

Answer 6

no that's me:)

yeah it is one of my dogs

Answer 7

yeah

Answer 8

sorry

Answer 9

Beautiful animal. As you may see my logo has my dog, a boston terrier.