Question

Given two spheres, if the volume of the first sphere is 3/4 pi and the volume of the second sphere is 36 pi , which is the relation of the second radius to the first?

Answer 1

its 4/3 NOT ---> 3/4 .

Answer 2

Do you remember the volume of a sphere formula?

Answer 3

no /:

Answer 4

is it 1/3 x pi x r x h ?

Answer 5

Ok, well it's V=(4/3)*pi*r^3

Answer 6

what does "^" mean ?

Answer 7

Oh, and you need to see the relationship btwn (4/3) and (36) too. Can you see what you need to multiply to (4/3) to get 36?

Answer 8

and "^" means "to the power of" so
\[V={4 \over 3} \pi r^{3}\]

Answer 9

Ok, well (4/3) times 27 gives us 36, so the second sphere has a volume 27 times greater than the first sphere's. Because the formula uses r^3, you can see that the radius grows exponentially. Set 27=r^3 and solve for r. The r stands for how much greater the second sphere's radius is to the first one's.

Answer 10

thank You !

Answer 11

no probs ^^