Question

The perimeter of a rectangular yard is 270 feet. if its length is 25 feet greater than its width, what are the dimensions of the yard?

Answer 1

270=2(25+w)+2w
Solve for w. Then solve 25+w to get your length.

Answer 2

thnx but i dont get it

Answer 3

hmm, well the perimeter of a rectangle is composed of 4 sides right? 2 of the sides are widths and 2 are lengths. Let's say w=width and l=length. Using these letters, the perimeter can be expressed as 2l+2w.

Answer 4

We know l is 25 more feet than w. So, l=25+w. If you substitute l with 25+w in the previous expression (2l+2w), you get 2(25+w)+2w. You were given the perimeter, so you set up the equation I first posted and solve for w to find the width. To find the length add 25 to whatever number you get as w. I hope that's less confusing.

Answer 5

thank you for explaining