Question

find the distance between the points (2,-3) (5,-4)

Answer 1

Use this formula

\[distance = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\]
where
\[(x_1,y_1) \space and \space (x_2,y_2) are \space the \space two \space points \space given\]

Now use this to find your answer

Answer 2

so the distance is 10 ?

Answer 3

Not exactly. It should be
\[\sqrt{10}\]

Answer 4

so does that mean i sqaure root it or it just stays that way?

Answer 5

See the formula again. The square root is present. You have not accounted the square root in the formula while working out the sum

Answer 6

so do i take the swuare root of 10?
cuz i just get 10.

Answer 7

\[\LARGE d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\]
\[\LARGE d=\sqrt{(5-2)^2+(-4-3 )^2}\]
\[\LARGE d=\sqrt{(3)^2+(-7 )^2}\]
\[\LARGE d=\sqrt{9+49}\]
\[\LARGE d=\sqrt{58}\]

Answer 8

@Kreshnik It should be - 4 +3 not -4-3. Check again

Answer 9

@shivam_bhalla You're right.. thanks for correcting me..

Answer 10

\[\LARGE d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2 }\]
\[\LARGE d=\sqrt{(5-2)^2+(-4-(-3))^2 }\]
\[\LARGE d=\sqrt{(3)^2+(-1)^2 }\]
\[\LARGE d=\sqrt{9+1 }\]
\[\LARGE d=\sqrt{10 }\]
:)

Answer 11

@RiyaMoon , I hope you now understand how we get sqrt(10) as the answer .

Answer 12

what the heck im confused......i just said square root 10 was the anwser and you told me it wasnt...

Answer 13

@RiyaMoon , you told me "so the distance is 10 ?"

Answer 14

yea then after you told me to look it over and i said so i have to take the square root of 10 which is 10.

Answer 15

@RiyaMoon , you told me
"so do i take the swuare root of 10?
cuz i just get 10."

??

Answer 16

nvm....

Answer 17

Ok. :D

Answer 18

hey guys, don't argue... the best way to avoid confusions is explaining it ;)

Answer 19

@Kreshnik , :D :D .