Question

Approximate the solution to 1 / square root of x^2 +1 = 1 / X + 5

Answer 1

\[\LARGE \frac{1}{\sqrt{x^2+1}}=\frac{1}{x+5}\]
use cross multiply and you'll get:

\[\LARGE \sqrt{x^2+1}=x+5\]
now square both sides...

brb

Answer 2

\[\LARGE (\sqrt{x^2+1}\;)^2=(x+5)^2 \]
squaring them what do you get? :)

Answer 3

\[X ^{2} + 1= (X+5)^{2}\] Then I would just solve for x right?

Answer 4

hmm... yes but...

\[\LARGE x^2+1=x^2+10x+25\]
\[\LARGE \cancel{x^2}-\cancel {x^2}-10x=25-1\]
\[\LARGE -10x=24\]
\[\LARGE x=-\frac{24}{10 }\]
simplify it.. :)

Answer 5

Okay, thank you

Answer 6

Glad to help :)