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let \[f(x,y)= xy((x^2-y^2/x^2+y^2) \] if \[x^2+y^2\neq0\] and define f(0,0)=0. Show that \[f_x (0,y)=-y\] and \[f_y (x,0) = x\] for all x and y. Then show that \[f_yx (0,0) = -1 \] and \[f_xy(0,0) = 1\].
f_xy are partials with respect to x and y. they just wouldn't let me double up on the underscore.
\[f_{xy}(0,0)=1\] f_{xy}(0,0)=1
this is a standard result that can easily be found using goggle.
like I said...2 sec on google... http://www.math.uconn.edu/~leibowitz/math2110f09/mixedpartials.pdf same function and everything
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Thank you
Hail Zarkon!
I showed the same problem to my multivariate calc students this semester :)
someone is mean. :D
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