Question

4 4
------ + ------ add
b+3 b^2-9

Answer 1

http://www4a.wolframalpha.com/Calculate/MSP/MSP31361a17197c01643eae000045eda44bdb998h65?MSPStoreType=image/gif&s=4&w=383&h=1337

Answer 2

to add fractions, you need the same denominators
in this case, you better factor that second denominator first
then multiply by whatever it takes to make the denominators the same
and then it is simple addition across the numerators

Answer 3

i dont need to solve for b i need to add the two

Answer 4

and for same denomenator it is b-3, b+3

Answer 5

yes

Answer 6

Little hint there:
(b+3)*(b-3) = b^2 - 3^2

Answer 7

Which is b^2 - 9

Answer 8

4(b-3) 4
------ + --------
(b+3)(b-3) (b+3)(b-3)

Answer 9

\[\frac{4(b-3)+4}{b^2 - 9}=\frac{4b-12+4}{b^2 - 9}=\frac{4b-8}{b^2 - 9}\]

Answer 10

my possible asnwers are

Answer 11

\[\frac{4b-8}{b^2-9} = \frac{4(b-2)}{(b+3)(b-3)}\]

:)