How would I solve for a: 5x(a+40)= 6x(a-40)
can you get all of the As on one side and the Xs on the other?
i've tred but it cant be done because you have to distribute and the a variable would turn into xa
I was looking at this wrong, sorry. I should have asked: What do you get when you multiply it out?
and yes, there will be Xs and AXs
5xa+200x = 6xa-240
there still is no way to solve for a
you forgot an X on the 240 there
now collect the terms.... the Xs on the left, the XAs on the right
200x + 240x = 6xa - 5xa right?
so then 440x = xa
ok, i see what you did
and what happens when you divide everything by X?
then you'll get 440 = a?
5x(a+40)= 6x(a-40) Faster way
divide both sides by x
distribute.
isolate the variable, and divide.
It's basically what @philips13 , but I just wanted to point out that you can divide by x in the first place.
there is a condition when you divide by any number, and x is the same: x cannot equal zero.
It would be more correct to add that x=/=0
yes, a=440 and I always do things the hard way, less confusing for me :D
Join our real-time social learning platform and learn together with your friends!