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Mathematics 4 Online
OpenStudy (anonymous):

How would I solve for a: 5x(a+40)= 6x(a-40)

OpenStudy (anonymous):

can you get all of the As on one side and the Xs on the other?

OpenStudy (anonymous):

i've tred but it cant be done because you have to distribute and the a variable would turn into xa

OpenStudy (anonymous):

I was looking at this wrong, sorry. I should have asked: What do you get when you multiply it out?

OpenStudy (anonymous):

and yes, there will be Xs and AXs

OpenStudy (anonymous):

5xa+200x = 6xa-240

OpenStudy (anonymous):

there still is no way to solve for a

OpenStudy (anonymous):

you forgot an X on the 240 there

OpenStudy (anonymous):

now collect the terms.... the Xs on the left, the XAs on the right

OpenStudy (anonymous):

200x + 240x = 6xa - 5xa right?

OpenStudy (anonymous):

so then 440x = xa

OpenStudy (anonymous):

ok, i see what you did

OpenStudy (anonymous):

and what happens when you divide everything by X?

OpenStudy (anonymous):

then you'll get 440 = a?

OpenStudy (inkyvoyd):

5x(a+40)= 6x(a-40) Faster way

OpenStudy (inkyvoyd):

divide both sides by x

OpenStudy (inkyvoyd):

distribute.

OpenStudy (inkyvoyd):

isolate the variable, and divide.

OpenStudy (inkyvoyd):

It's basically what @philips13 , but I just wanted to point out that you can divide by x in the first place.

OpenStudy (inkyvoyd):

there is a condition when you divide by any number, and x is the same: x cannot equal zero.

OpenStudy (inkyvoyd):

It would be more correct to add that x=/=0

OpenStudy (anonymous):

yes, a=440 and I always do things the hard way, less confusing for me :D

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