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Mathematics 17 Online
OpenStudy (chrisplusian):

need help with an indefinite integral

OpenStudy (lgbasallote):

i need to practice on integrals so i'll help :P

OpenStudy (chrisplusian):

can someone explain how\[\int\limits_{?}^{?}1/\theta^2 \cos(1/\theta)d \theta becomes -\sin(1/\theta)+c\]

OpenStudy (chrisplusian):

I couldn't find the integral symbol without bounds so I just put them blank

OpenStudy (lgbasallote):

lol you just have to erase the ? anyway.... let me try to fix this.... \(\large \int \frac{1}{\theta ^2} \cos (\frac {1}{\theta} ) d \theta = -\sin (\frac{1}{\theta} ) + C \) that's the question correct?

OpenStudy (anonymous):

\[\int \frac{\cos(\frac{1}{\theta})}{\theta^2}d\theta\]

OpenStudy (anonymous):

i will be quiet, just wanted to write it

OpenStudy (chrisplusian):

the one that igbasallote posted

OpenStudy (anonymous):

lol ok

OpenStudy (zarkon):

lol

OpenStudy (lgbasallote):

well then i'll give you a hint... let u = \(\large \frac{1}{\theta}\) du = \( \large \theta ^{-1} = -1(\theta ^{-2}) = - \frac{1}{\theta ^2}\) can you see how to do it now?

OpenStudy (lgbasallote):

:O @Zarkon you're mod too??? wow congrats!

OpenStudy (zarkon):

ty

OpenStudy (anonymous):

@Zarkon congrats on being a mod. damn everyone but me? jealous

OpenStudy (chrisplusian):

what is mod?

OpenStudy (anonymous):

maybe in the next draft pick

OpenStudy (lgbasallote):

haha lol yeah satellite i noticed too =)) you deserve to be one after all your contributions to this site ^_^

OpenStudy (lgbasallote):

@chrisplusian mods are moderators kind of the ones who overlook the site..global moderators have great prestige because it means they are the best in their subject...anyway back to your question :D

OpenStudy (chrisplusian):

you guys/ girls are awesome. I can't find help at my $240 a credit hour school so I come here:)

OpenStudy (lgbasallote):

do you know how to go from that substitution @chrisplusian ?

OpenStudy (chrisplusian):

yes i have it. because du is one over theta squared, d theta. and when I differentiate theta to the negative first it becomes one over d thaeta squared times d theta. I would have never seen that on my own. Thanks

OpenStudy (zarkon):

@satellite73 maybe :)

OpenStudy (lgbasallote):

it just takes practice :DDD just remember that when substituting..ALWAYS substitute the more complicated one

OpenStudy (anonymous):

probably doesn't help that i am still trying to stay relatively anonymous

OpenStudy (chrisplusian):

what makes it more complicated? the fact that it is the argument of a trig function?

OpenStudy (lgbasallote):

yup :DD

OpenStudy (lgbasallote):

by the way...i think the frontrunners for the next mod picking is satellite and hero..well i think they're the most deserving ones haha

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