Question

SOMEONE HELP ME SOLVE THIS PLEASE.

Answer 1

\[\left[\begin{matrix}5 & -7 \\ -3 & 4\end{matrix}\right] \times \left[\begin{matrix}a & b \\ c & d\end{matrix}\right]=\left[\begin{matrix}1 & 0 \\ 0 & 1\end{matrix}\right]\]

Answer 2

Doesn't make much sense to me, you mind further explaining?

Answer 3

mind telling me the answer quickly? i have no calculator at the moment.

Answer 4

http://en.wikipedia.org/wiki/Inverse_matrix#Inversion_of_2.C3.972_matrices

Answer 5

answer anyone?

Answer 6

I keep getting off the wall answers.

Answer 7

The inverse of a matrix A is

(1/det (A)) * adjugate(A)

This means that the inverse is simply the one over the determinant of the matrix times the adjugate of matrix A.

the determinant of your matrix is= (5*4)-(-3*-7)= 20-21= -1

so 1/-1 = -1

the adjugate of a 2x2 matrix is
d -b
-c a

Answer 8

since you're finding the inverse, you need to find the values of a, b, c, and d as Paxpolaris stated.

Answer 9

That's my question would -1 be my answer?

Answer 10

YOUR answer is a matrix

Answer 11

You really need to review this section. If you didn't know the answer is a matrix your way off.

Answer 12

4,7
3,5

Answer 13

correct?

Answer 14

times negative 1 don't forget about the determinant

Answer 15

totally confused. but thanks guys

Answer 16

\[\left[\begin{matrix}-4 & -7 \\ -3 & -5\end{matrix}\right]\]

Answer 17

THANK YOU!!!!!!