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OpenStudy (anonymous):
Write this expression has a single logrithim:
5 log base 7 of x - 2 log base 7 of x
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OpenStudy (anonymous):
\[5 \log_{7}x-2\log_{7}x \]
OpenStudy (anonymous):
do you know the properties of logs and utilizing them?
OpenStudy (lgbasallote):
first you might wanna use the power rule..it states that
\( \LARGE a log_b x = log_b x^a\)
OpenStudy (kropot72):
log to base 7 of x is a common factor. Therefore to solve take out the common factor.
OpenStudy (anonymous):
this is the quotient property
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OpenStudy (lgbasallote):
then you use the quotient law :P
OpenStudy (anonymous):
Could you give me an example?
OpenStudy (lgbasallote):
quotient law:
\(\LARGE \log_a b - log_a c = \log_a (\frac{b}{c})\)
OpenStudy (anonymous):
\[\log_{7} (x^5/x^2)\]
OpenStudy (anonymous):
Am i headed in the right direction?
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OpenStudy (lgbasallote):
not just headed...you got it! :DDD \(\Huge \color{red}{\checkmark}\)
OpenStudy (lgbasallote):
oh wait...there's still one last step...
OpenStudy (lgbasallote):
you still need to simplify the argument (the number inside the parenthesis) @amy_renae1994
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