Write this expression has a single logrithim: 5 log base 7 of x - 2 log base 7 of x
\[5 \log_{7}x-2\log_{7}x \]
do you know the properties of logs and utilizing them?
first you might wanna use the power rule..it states that \( \LARGE a log_b x = log_b x^a\)
log to base 7 of x is a common factor. Therefore to solve take out the common factor.
this is the quotient property
then you use the quotient law :P
Could you give me an example?
quotient law: \(\LARGE \log_a b - log_a c = \log_a (\frac{b}{c})\)
\[\log_{7} (x^5/x^2)\]
Am i headed in the right direction?
not just headed...you got it! :DDD \(\Huge \color{red}{\checkmark}\)
oh wait...there's still one last step...
you still need to simplify the argument (the number inside the parenthesis) @amy_renae1994
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