Forces with magnitudes of 70 pounds, 40 pounds, and 60 pounds act on an object at angles of -30, 45, and 135, respectively, with the positive x axis. Find the direction of the magnitude of the resultant of these forces
The resultant x-component is: 70cos(- 60) + 40cos(45) + 60cos(120) = 33.284 pounds. The resultant y-component is: 70sin(- 60) + 40sin(45) + 60sin(120) = 19.624 pounds. The resultant is: sqrt(33.284^2 + 19.624^2) = 38.6 pounds to 3 sig. fig. If t is its direction measured from the positive x-axis: tan(t) = 19.624 / 33.284 Both x- and y-components are positive, indicating a quadrant 1 angle: t = 30.5 deg.
This has incorrect points
isn't this physics?
then again, physics is maths
I'm looking for -30, 45, and 135
there's too little data for the previous question ket-kat
There's enough, I just need to know how to set it up
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