Question

Factor completely: 3x^2+17+10 I need some help with the steps to figure this out.

Answer 1

= 3x^2 + 27 [Adding 17 + 10]
= 3(x^2 + 9) [Factoring]

Answer 2

ParthKohli, is that the full answer? I'm looking for a complete example so I know how to do the next questions.

Answer 3

Yes. that is the answer. You just have to find out the common factors in both and put that out of the bracket. Can you give another so I can explain?

Answer 4

5y8 - 125

Answer 5

Okay. So, a common factor you find in both is 5(125 is divisible by 5)

Answer 6

So, you put the 5 out of the bracket. Now what do you have to multiply to 5 to get 5y^8?

Answer 7

5 * y^8 = 5y^8, agree? And now 5 * 25 = 125, agree again?

Answer 8

So 5(y^8 - 25) is the answer

Answer 9

Alright, I'm getting the hang of this. Thank you!

Answer 10

I can explain more if you wanna perfect this. No problem btw ;)

Answer 11

There's a2 - 2ab - 15b2 if you don't mind c:

Answer 12

Of course :D

Answer 13

This is a quadratic expression. It has a different method. Search it on google. Although I'm gonna solve it for you.
=> a2 -5ab + 3ab - 15b2
=> a(a - 5b) + 3b(a - 5b)
=> (a + 3b)(a - 5b)

Answer 14

Do you want me to explain this type of factorization?

Answer 15

I'll search on google to spare you from typing, haha.

Answer 16

Haha....

Answer 17

How about 4c2 - 12c + 9?

Answer 18

Let's see..

Answer 19

4c2 - 6c - 6c + 9
= 2c(2c - 3) - 3(2c - 3)
= (2c - 3)(2c - 3)
\[\LARGE => {(2c - 3)}^{2}\]

Answer 20

\[\Huge \text {CAN I HAVE A MEDAL PLEASE?}\]

Answer 21

How do I give you one?

Answer 22

Click that Best Answer thingy in my answer

Answer 23

\[\Huge \text {THANKS :D}\]

Answer 24

No problem c:
Thank you!!