Question

Solve. Please show steps.
lnx-ln(x-1)=1

Answer 1

use \[\ln(\frac{a}{b})=lna-lnb\]

Answer 2

then use \(\large \log_a b = c \rightarrow a^c = b\)

Answer 3

easier way take e of both sides since its ln

Answer 4

as the queen orders...

\(\ln a = x \rightarrow e^x = a\)

Answer 5

hehe try it @Chena804

Answer 6

integration?

Answer 7

\[\ln x-\ln (x-1)=1\]
\[\ln (x \div(x-1))=1\]
\[\left(\begin{matrix}x\\ x-1\end{matrix}\right)=e ^{1}\]
\[x=(x-1)e ^{1}\]

You can solve the rest. ;)