find the soloutions of the system:
y=x^2+3x-4
y=2x+2

Question

find the soloutions of the system:
y=x^2+3x-4
y=2x+2

anonymous · Answer

Start by rearranging the second equation:
$$x = \frac{1}{2}(y-2)$$
Substitute that into the first one and expand. What do you get?

anonymous · Answer

Or perhaps more simply, solve the equation:
$$2x+2 = x^2+3x-4$$

radar · Answer

I like that MathBoy,  Transpose getting $$x ^{2}+x-6$$ can easily be factored and solved

radar · Answer

should of put "=0" at the end. lol

radar · Answer

clara_summer1, that you can do.

radar · Answer

Can you handle that now?

radar · Answer

@clara_summer1, are you sincerely interested in learning how to solve this?

anonymous · Answer

yes, i ve a child and it was very hard sitting down, sorry.

radar · Answer

O.K.  Sorry,  Do you know how to factor that in order to solve it?  If not, I will show you.

anonymous · Answer

no, sorry

radar · Answer

$$x ^{2}+x-6=0$$
(x+3)(x-2)=0   These are the factors, since they result in 0 one or both have to be 0
x+3=0    and  x-2=0
x=-3
x=2

anonymous · Answer

ok so how to we get to the y?

radar · Answer

Factoring becomes easier with practice.  but you are looking for factors that will result first  in x^2   That is easy as it has to be x|dw:1335536998523:dw|Now we have to find factors when mulltiplies will result in a -6, and when combined will result in a 1 as we have 1x.