Question

What is the 6th term of the geometric sequence where a1 = 625 and a3 = 25?

Answer 1

a1 = 625
a3 = sqrt of a1
a5 = sqrt of a3
a7 = sqrt of a5

Answer 2

a5 = 1
a7 = 1/25

Answer 3

a6 = 1/5

Answer 4

a1 = 625
a3 = 625 / q² .... ( q = 5)
....

Answer 5

a=625

625r^2=25
r^2=5/125
r=sqrt(5/125)

ar^6=625(sqrt(5/125)^5)

Tap on your calculator and you should get your answer.

Answer 6

And sorry... the ar^6 should be ar^5. The formula is ar^(n-1) after all.

Answer 7

so what do i plug in the calculator?

Answer 8

\[\LARGE a _{x} = {3125 \over 5x}\]

Answer 9

yeah and thats the same for ax = 625/x ... you just multiplied 5 :)

Answer 10

625 isnt right

Answer 11

Key in this:
625(sqrt(5/125)^5)
sqrt is the square root.