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The solution of a certain differential equation is of the form y(t) = a exp(2 t) + b exp(5 t), where a and b are constants. The solution has initial conditions y(0) = 3 and y'(0) = 5 . Find the solution by using the initial conditions to get linear equations for a and b.
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so the given solution is\[y(t)=Ae^{2t}+Be^{5t}\]and you want to find A and B given the initial conditions?
...correct?
Yes :)
what is y'(t) ?
..and sorry for the late reply
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find y'(t) the plug t=0 into each equation y(0)=3 y'(0)=5 this will give you a linear system of two equations that can be solved for A and B
Can you tell me what you get for the linear system, I don't think I did it right :/
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