Find the radius of convergence if |3x+2| lim n->inf a_n <1, and the limit equals 1. The answer is {2/6}, but i dont understand why. See complete problem below.
\[|3x+2| \lim_{n \rightarrow \infty} an <1\] \[|3x+2| <1\] = \[-1<3x+2< -1\] = \[-1< x < -1/3\] and some how, radius of convergence= {2/6}
radius of convergence is the distance from the midpoint to an and point
end point that is
as such, radius is going to be postive in value
now you sure its 2/6? which equals 1/3
Thats what he said and wrote on the board. Which is also y i was a bit confused. Its as if he multiplied spomething to get that number, even though I could just simply to get 1/3
thats what i would have done. Teachers do unnecessary things sometimes
also, notice that the midpoint of -1 to -1/3 add and divide in half 1+1/3 = 4/3 4/3 ---- = 4/6 = 2/3 2 so the 2/6 might be a typo
Ah, okay. Thanks!
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