Question

if -q1q2/2 = (q1+q2)^2
then find q1/q2;

Answer 1

\[-\frac{q_1 q_2}2 = q_1^2 + q_2^2 + 2q_1 q_2\]
\[-\frac12 = \frac {q_1}q_2 + \frac{1}{\frac{q_1}{q_2}} + 2\]
Let \(\frac{q_1}q_2 = k\) and solve it.

Answer 2

You will get a quadratic equations in terms of k.

Answer 3

hey yeah i got it as -3/4 :

Answer 4

sorry no thats not what i got :

Answer 5

i got -2 or -1/2

Answer 6

0=k^2 + 1 + 5/2k, assuming k isn't zero
2k^2 + 2 + 5k = 0

http://www.wolframalpha.com/input/?i=2k%5E2+%2B+2+%2B+5k+%3D+0+

-2 and -1/2. so you're right.

Answer 7

thanks a lot.