Calculate the definite x integral of 2+3x=y from x=3 to 10 Show steps please
First you want to calculate the antiderivative of 2+3x. Let's call that F(x). I you have that the answer will be F(10)-F(3). Do you know how to calculate F?
No asume I know nothing because I have confused myself
The idea of the antiderivative is the following: if you derive it you'll get back at the original function. So dF(x)/dx=2+3x You compute the antiderivative of a polynomial as follows: add one to the degree of every term and divide by the degree +1. Some examples: antiderivative of x: degree is one, add one to the degree to get 2 and divide by 2: we get 1/2 x^2 antiderivative of 2X^3+6: for the first term we get 2/4 x^4, the degree of the the second term is 0, so we get 6/1 x. all in all we get 1/2 x^4+6x
Is it clear so far?
I think so keep going
If you're with me so far, can you compute the antiderivative of 2+3x?
\[1+(3/2)^2\]
what's the derivative of that?
is that correct before I do
nope, sorry, you'll see when you compute the derivative.
I got 0 as the derivative of my antiderivative
Right, but it should be 2+3x, so it's not correct.
ok
You left out the x's in your antiderivative. It should be 2/1 x + 3/2 x^2. which simplifies to 3/2 x^2+2x Clear?
is it \[(((3x)^2)/2) + 2x\]
oh i see your now
what is the next step
So the 3 isn't squared. We have F(x)=3/2 x^2 +2x. Now you need to compute F(10)-F(3)
so just plug 3 in and 10 in and get two answeres and then subtract the answer from 3 from 10
that's right.
ok let me works it
I got f(10) = 170 and f(3) = 33/2
is this correct?
F(3) is something else I believe.
got 39/2.... sorry... so final answer 150.5 or 301/2
Thanks so much!!!
could you help me with another
Great, Also, the uppercase ia important in the notation: F(x) denotes the antiderivative of f(x)
ok
\[\int\limits_{?}^{?} 2e^{5x} dx\]
all it says is to solve
When there are no boundaries in you integral you have an indefinite Integral. So earlier we had the boundaries 3 and 10, that was a definite integral, now we have an indefinite one. This means that we don't have to the second step of computing F(upper bound)-F(lower bound), we just need to compute the antiderivative of 2e^(5x)
ok I will try
When you derive a power of e you multiply by the constant in front of the x right? So d/dx e^(4x)=4e^(4x). The derivative of our antiderivative should 2e^(5x). So we need to compensate for the 5 you get when deriving the antiderivative.
meaning?
2e^5 x\[2e^5 x\]
It's 2e^(5x), right?
yes you are right
The antiderivative here is the original function divided by 5. So F(x)=2/5 e^(5x). (*) So you can compute the derivative of this, see if it's correct. * this isn't completely true, we'll talk about that later.
so the antiderivative is \[(2e ^{5x})/5\]
right, but let's talk about (*). What's the derivative of 2/5 e^(5x) +1?
it is the original 2e^(5x)
So apperently 2/5 e^(5x)+1 is also an antiderivative.
ok so what do i need to do with that information
You can add any constant to the antiderivative and still get an antiderivative, so we denote this by adding +C, to the answer. So the actual solution to the integral here is 2/5 e^(5x)+C. You always need to add that C if you compute indefinite integrals, it's not important in definite integral.
oh ok I see. that was explained in the book but no clear at all Thanks again you were a huge help
great, you're welcome.
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