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Mathematics 15 Online
OpenStudy (anonymous):

Please see the attached image. I do not understand how I am going to go from f(x) to f''(x)....

OpenStudy (anonymous):

image?

OpenStudy (anonymous):

Wait

OpenStudy (anonymous):

OpenStudy (anonymous):

There

OpenStudy (anonymous):

f(x) = 2 ( x -2) +1 Can you continue to find f'(x) and f"(x)?

OpenStudy (anonymous):

i dont think we can just assume that is f, there may be other functions that satisfy those conditions have you tried integration by parts?

OpenStudy (anonymous):

How do I know what f is? Sorry I do not know where to start for this one. I am clearly lost for this one.

OpenStudy (anonymous):

have you done integration by parts before?

OpenStudy (anonymous):

its the reverse of the product rule:\[\int\limits{g'(x).f(x)}dx = f(x)g(x) - \int\limits{f'(x).g(x)}dx\]

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

OHHH! So you are suggesting to do integration by parts on the one with the second derivative!

OpenStudy (anonymous):

\[\int\limits^2_0{x^2 f''(x)}dx = [x^2f'(x)]^2_0 - \int\limits_0^2{2x f'(x)}dx\]

OpenStudy (anonymous):

Wow! It just hit me right now.

OpenStudy (anonymous):

something like that :)

OpenStudy (anonymous):

OMG! I need to review my integration properties. My final is tomorrow. Thank you for your help. ALSO, I have one more question if you do not mind. I think I can deal with this one now that I know I need to use integration by parts

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

I just need to attach it, give me a minute

OpenStudy (anonymous):

I will message you when I post it.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

OpenStudy (anonymous):

Ok I posted it.

OpenStudy (anonymous):

daamn what level maths is this?

OpenStudy (anonymous):

ok dont worry the definition is included

OpenStudy (anonymous):

This is Calculus first year.

OpenStudy (anonymous):

ah as in a degree? im just curious :)

OpenStudy (anonymous):

No this is first year in university ever.

OpenStudy (anonymous):

how are you finding it? (dont worry im still looking at your problem)

OpenStudy (anonymous):

Math is the hardest. The sciences are pretty straightforward, given you follow the instructor's warnings about the exam.

OpenStudy (anonymous):

But this is from my opinion. To me, it looks like it would be easy for you (ie. math)

OpenStudy (anonymous):

im fairly sure the lower limit is -5, i just have to go and get a drink, brb

OpenStudy (anonymous):

sorry i dont quite understand, are you starting a math degree? what are you studying for? (im sorry if this is me being stupid)

OpenStudy (anonymous):

no the lower limit is not -5

OpenStudy (anonymous):

i havent seen any maths like this before unfortunatly

OpenStudy (anonymous):

The big issue i am having with this problem is the n^2 in the denominator. I have never been exposed to such a case.

OpenStudy (anonymous):

ah ok. so can you see that the interval is -5 to 23 ?

OpenStudy (anonymous):

im not really using a standard method here as i haven't been taught anything on integration as a limit of a summation yet

OpenStudy (anonymous):

consider the first term of that summation, i = 1 we have the term: \[\frac{7 \times14}{n^2}f(-5 + \frac{28}{n})\]

OpenStudy (anonymous):

and we know that x* satisfies \[a<x*<a+ \Delta x\] for all n

OpenStudy (anonymous):

and\[ x^* = -5 + \frac{28}{n}\] \[a< -5 + \frac{28}{n} < a + \frac{(b-a)}{n}\]

OpenStudy (anonymous):

if we take n>0 then the only a which satisfies the first part of the ineq. is a = -5

OpenStudy (anonymous):

hmm i think we need \[\le\] in the second part.. im sorry i cant help that much, i havent studied this yet. i will probably cover this stuff next year at university

OpenStudy (anonymous):

It is alright. Thanks for your help with the previous question.

OpenStudy (anonymous):

no problem :) @experimentX @TuringTest @Foolformath can probably help

OpenStudy (experimentx):

???

OpenStudy (anonymous):

See attached

OpenStudy (anonymous):

Or look at this one:

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

Any ideas?

OpenStudy (anonymous):

Hey try this one I posted just now eigen. Do you know this one?

OpenStudy (anonymous):

noo are these riemann sums? i have a calculus book im self teaching but i havent got that far yet

OpenStudy (anonymous):

still on its differentiation section

OpenStudy (anonymous):

i can see how they are identical, i'm struggling to express it mathematically

OpenStudy (anonymous):

its because n tends to infinity, so the first term tends to f(1) in both series, and f(1 + (i-1)/n) tends to f(1 + i/n) for all integer i

OpenStudy (anonymous):

(i think)

OpenStudy (experimentx):

looks like upper and lower Riemann sums

OpenStudy (anonymous):

show they become the same integral then?

OpenStudy (experimentx):

any information given on the continuity of function??

OpenStudy (anonymous):

For which one experimentX?

OpenStudy (anonymous):

Ok let me post out the entire question. Those were only two of the choices given.

OpenStudy (anonymous):

OpenStudy (experimentx):

c) definite integral gives the area under the curve.

OpenStudy (experimentx):

looks like d) the lower and upper Riemann sums also give the area under the curve.

OpenStudy (experimentx):

http://pirate.shu.edu/~wachsmut/ira/integ/riemann.html Lemma 7.1.10: Riemann Lemma

OpenStudy (anonymous):

How is "a" the same as "b"? I have been trying to get to what they showed in (a) but I wasn't able to. How did they get the one in (a)?

OpenStudy (experimentx):

they will not be same ... as n tends to infinity, they will be close enough to each other.

OpenStudy (anonymous):

So then why is it that all of the above is the answer?

OpenStudy (experimentx):

because that is right ... 1/n will be finitely small for large value of n, similarly, f(1 + i/n) and f(1 + i-1/n) will have close value, so they will be almost same.

OpenStudy (experimentx):

if we can determine a number epsilon > 0 such that the difference of two sums is less than epsilon, it proves that they are very close to each other.

OpenStudy (anonymous):

Ok I understand. I will keep that in mind. There is one more question, if you are still willing to help. Its alright if you have other things to do.

OpenStudy (experimentx):

yeah ... go on

OpenStudy (anonymous):

Ok it is this question. Let me just attach it.

OpenStudy (anonymous):

Pesky n^2.... >_<

OpenStudy (anonymous):

How would I go about with this problem?

OpenStudy (experimentx):

somehow looks like a or c, but ... there's stupid front part.

OpenStudy (experimentx):

b also fits form the point of view of limit.

OpenStudy (experimentx):

i/n = somehow x

OpenStudy (anonymous):

That n^2 is throwing me off. I am not used to that. I am just used to seeing: f(xi)*delta x format Where delta x = b-a/n

OpenStudy (experimentx):

i/n must be somehow related to x, and 1/n is equivalent to dx

OpenStudy (anonymous):

you mean the \(n^2\) in the denominator?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

In the boxed: That is what I am used to seeing:

OpenStudy (anonymous):

where delta x = (b-a)/n

OpenStudy (experimentx):

7 is giving the trouble ...

OpenStudy (experimentx):

i think without 7 it will be equal to b)

OpenStudy (anonymous):

one n in the denominator is from \(\Delta x\)

OpenStudy (experimentx):

Oo.. still wrong.

OpenStudy (experimentx):

the other i/n is related to x

OpenStudy (anonymous):

Then what do I do with the other n?

OpenStudy (experimentx):

THE OTHER N IS RELATED TO X ALONG WITH i

OpenStudy (anonymous):

man now this is bugging me.

OpenStudy (experimentx):

|dw:1335573189252:dw| If there were no 14, then b would have been correct.

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