A direct current power supply is connected to a circuit containing one resistor, and 1.5 A is drawn. If a second identical resistor is connected to the power supply in parallel with the first, how much current is drawn from the battery?
6.0 A
0.75 A
3.0 A
1.5 A

Question

A direct current power supply is connected to a circuit containing one resistor, and 1.5 A is drawn. If a second identical resistor is connected to the power supply in parallel with the first, how much current is drawn from the battery?
	6.0 A
	0.75 A
	3.0 A
	1.5 A

anonymous · Answer

the power supply is a DC battery battery.let it's emf be E.now use ohm's law in case 1 to get the value of e in terms of r(resistance).similarly use ohm's law in case 2 and u 'll be able to find out the ans on ur own

experimentx · Answer

voltage source remains constant while the resistanceis doubled ... use ohm's law.

anonymous · Answer

Both are right.  :D

anonymous · Answer

@experimentX this is exatly what i was going to say .when u in increse resistance ,current will drop as it is inversly prop to resistance

anonymous · Answer

No ExperimentX is not right .  Resitance becomes half parallel connection

experimentx · Answer

Oo .. sorry, didn't read the question well  ... indeed!!!

anonymous · Answer

sorry i mentioned the reverse case

anonymous · Answer

I mean effective resistance

anonymous · Answer

effective resistance will be half of the value in case 1.so current will be two time s that in case1

anonymous · Answer

The more resistors you connect in parallel, the more current you draw from the power supply. Imagine you connect a second lamp to a power supply already providing current to a lamp. What will the total current be if the lamps are identical? but i still undereerstand

anonymous · Answer

depends on how they are connected(in series or in parallel)

anonymous · Answer

Proof

$$V=IR$$
Case 2  Resistance = R/2
|dw:1335567776786:dw|
$$V=I'R' = I'(R/2)$$