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2=log x +log (x+48) solve
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ok, so log(a) + log(b) = log(ab) this means we can group together on the RHS 2 = log(x(x+48)) now we want to get rid of the logs assuming this is the common base 10 logarithm we raise 10 to the power of each side: 10^2 = 10^log(x(x+48)) now the log and the 10^ cancel leaving 100 = x(x+48) do you follow the steps up to there?
can't be more clear than that...
:D i could have explained why they cancel i suppose
Thanks Still a little confused
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