p/q=(sqrt(2))
not if p and q are integers
Huh? I know what integers are, but how does that work?
what you wrote is this \[\frac{p}{q}=\sqrt{2}\] but \(\sqrt{2}\) cannot be expressed as the ratio of two integers, so it does not work!
What is the question exactly?
Unless p and q are real then we can
the question is what are you doing here on a friday night, instead of being out eating pizza and drinking margaritas
They do not have to be real.
What are we doing with this p/q=sqrt(2) thing? Does it say anything else in the instructions?
Actually, I am just doing this to see if I can express irrational numbers as a ratio of any 2 numbers, therefore the numbers do not have to be real. They can be imaginary (sqrt(-x))
\[\sqrt{2}=\frac{\sqrt{2}}{1}=\frac{2}{\sqrt{2}}\] Can be expressed many ways
Nice!
But if you want p/q=sqrt(2) where p and q are integers then there is no such fraction since sqrt(2) is irrational like sat was saying
So you cannot use 2 integers to express a ratio for an irrational number.
Is that correct?
That is totally right
Ok. Bye!
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