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Mathematics 14 Online
OpenStudy (anonymous):

p/q=(sqrt(2))

OpenStudy (anonymous):

not if p and q are integers

OpenStudy (anonymous):

Huh? I know what integers are, but how does that work?

OpenStudy (anonymous):

what you wrote is this \[\frac{p}{q}=\sqrt{2}\] but \(\sqrt{2}\) cannot be expressed as the ratio of two integers, so it does not work!

myininaya (myininaya):

What is the question exactly?

myininaya (myininaya):

Unless p and q are real then we can

OpenStudy (anonymous):

the question is what are you doing here on a friday night, instead of being out eating pizza and drinking margaritas

OpenStudy (anonymous):

They do not have to be real.

myininaya (myininaya):

What are we doing with this p/q=sqrt(2) thing? Does it say anything else in the instructions?

OpenStudy (anonymous):

Actually, I am just doing this to see if I can express irrational numbers as a ratio of any 2 numbers, therefore the numbers do not have to be real. They can be imaginary (sqrt(-x))

myininaya (myininaya):

\[\sqrt{2}=\frac{\sqrt{2}}{1}=\frac{2}{\sqrt{2}}\] Can be expressed many ways

OpenStudy (anonymous):

Nice!

myininaya (myininaya):

But if you want p/q=sqrt(2) where p and q are integers then there is no such fraction since sqrt(2) is irrational like sat was saying

OpenStudy (anonymous):

So you cannot use 2 integers to express a ratio for an irrational number.

OpenStudy (anonymous):

Is that correct?

myininaya (myininaya):

That is totally right

OpenStudy (anonymous):

Ok. Bye!

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