6.In a 45°- 45°- 90° right triangle, the length of the hypotenuse is 15. How long are the legs?
wait so the other two "legs" are the same right?
your confusing me
sure because two angles are the same
how are you confused?
I dont understand how to get the numbers or anything, i was out the day my teacher taught this and dont get it at all
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you have one 90 degree angle, and two 45 degree angles so the legs of the right triangle are equal in length
so when i divide 90 by sqrt 2 i get 45 sqrt 2. what does that mean?
i have confused you, forget what i wrote and lets start again from the beginning
oh ok
is it ok that both legs of the triangle have the same length?
because both angles are the same
yes
ok then lets call them something. lets call them "a"
ok
now lets find the lenght of the hypotenuse using pythagoras
we know pythagoras says \(a^2+b^2=c^2\) for a right triangle yes?
yes
45^2+45^2=90^2
hold on
45 45 90 is not the measure of the lengths of the sides, it is the measure of the angles
pythagoras is about the lengths of the sides, not the message of the angles
oh...then what do we do for this problem?
i am getting to that
s-sorry..
we start with \[a^2+b^2=c^2\] right? but since the lengths of the legs are both "a" we replace b by a and write \[a^2+a^2=c^2\] ok?
now we write \(a^2+a^2=2a^2\) so we have \(2a^2=c^2\) and we want to find c
okay so then it would be 45^2 +45^2=90^2 ? right?
take the square root to find the length of c. we get \[\sqrt{2a^2}=c\]
and we know that \[\sqrt{a^2}=a\] so what we really have is \[\sqrt{2}a=c\]
so 4050= 90^2?
in other words, in plane english, if i know the lengths of the sides of a 45-45 -90 right triangle, then i can find the hypotenuse by multiplying by \(\sqrt{2}\)
and if i know the length of the hypotenuse, i can find the length of the sides by dividing by \(\sqrt{2}\)
im still confused.....this isnt helping me very much
please don't square the measures of the angles. it is the lengths of the sides ok let me say it as simply as i can your hypotenuse is 15 right? the length of the side is therefore \(\frac{15}{\sqrt{2}}\)
how do i solve the problem........ i understand that is the length of the side....is that the anwser?
yes
if you want a decimal use a calculator and find \(15\div \sqrt{2}\)
but its asking for how long the legs are... not the sides
the legs are the sides
they are synonyms
so all the legs eqaul 15/ sqrt 2
yes
yes, both legs have length \(\frac{15}{\sqrt{2}}\)
if i knew the lenght of the legs was 10, then the length of the hypotenuse would be \(10\sqrt{2}\) and if i know that the length of the hypotenuse is 50 then i know the length of the legs is \(\frac{50}{\sqrt{2}}\)
in other words, so find the hypotenuse multiply by \(\sqrt{2}\) and do find the legs divide the hypotenuse by \(\sqrt{2}\)
|dw:1335577257030:dw| By Mr. Pythagoras and his Pythagorean theorem we have \[a^2+a^2=15^2\] Where a is the length of the legs \[2a^2=15^2\] \[a^2=\frac{15^2}{2}\] \[a=\sqrt{\frac{15^2}{2}}=\frac{\sqrt{15^2}}{\sqrt{2}}=\frac{15}{\sqrt{2}} \] I know this is what sat already said. I just thought maybe I would give a go at explaining it since there still seemed to be confusion.
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