Question

working on measures of spread activity.. having problems with creating a probability distribution for this experiment

Answer 1

What is your question exactly?

Answer 2

whats the experiment? and is that like a frequency distribution?

Answer 3

roll a die 50 times

Answer 4

well 6 outcomes times 50 = 300 total outcomes

Answer 5

1/6 by 50 is a uniform probability distribution

Answer 6

no it aint ... but its still a uniform distributio

Answer 7

what about rolling the die are you probably distributing?

Answer 8

you take the number and double it

Answer 9

roll a die 50 times, take the number and double it. which number?

Answer 10

if you roll a one you get a two.. if u roll a 6 you get a 12

Answer 11

ok .....

Answer 12

Roll a single die and double the number you roll (i.e. if you roll a 4, the outcome is 8.)

Answer 13

2. Create a probability distribution for this experiment. What do you notice about the probabilities for each outcome?

Answer 14

i still dont get where the 50 times to roll it plays in

Answer 15

face value ; probability

1 1/6
2 1/6
3 1/6
4 1/6
5 1/6
6 1/6

Answer 16

its just part of the activity

Answer 17

so is this spose to be based on experimental data collected form the activity? as opposed to the pure stats?

Answer 18

yeah.. its all experimental.
how do you find the expected value of the distribution

Answer 19

expected value is expected reward times probability

Answer 20

summed up

Answer 21

how do you get a reward with dice?

Answer 22

2 * collected data
4 * collected data
6 * collected data
8 * collected data
10 * collected data
12 * collected data
-----------------
summed up = total expected value

Answer 23

the reward is the point value you receive

Answer 24

2 0.167 0.334
4 0.167 0.668
6 0.167 1.002
8 0.167 1.336
10 0.167 1.67
12 0.167 2.004
7.014

Answer 25

so the 7.014 is the expected reward?

Answer 26

if you play a game and want to know your expected value:

say winning gets you $5, but if you lose you are out $3

the pro of winning is .3 and the prob of losing if .7

expected value = 5*.3 + -3*.7 = 1.5 - 2.1 which is a high risk

Answer 27

yes, if that experimental probabilities are what you gathered there

Answer 28

ok, thank you
not really educated on the probability stuff.. its extra credit and i need all the help i can get on math

Answer 29

im so-so at prob and stats; what i forget i tend to look back up to review :)

Answer 30

yeah, my 99 doesnt change lol

Answer 31

well thats cuz u gotta turn ur gold stars into the teacher to get ur soda for movie day

Answer 32

you mean hording them is soo passe' ?

Answer 33

maybe

Answer 34

well, good luck ;)

Answer 35

or u just gotta wait for your mom to buy a new fridge cuz she doesn't take down any stickered papers

Answer 36

thanks for the help..

Answer 37

youre welcome