An optimization problem...

Question

anonymous · Answer

attachment

anonymous · Answer

I am having trouble coming up with the equation for this. I know that similar triangles are involved to get it, but that is as best as I know so far..

anonymous · Answer

A = xy

anonymous · Answer

Is there any option, I found A/2 but I am not sure..

anonymous · Answer

But how can you reduce the equation down to one variable?

anonymous · Answer

$$Area = \int\limits_{}^{}{A \over x}  \space dx$$

anonymous · Answer

Ok suppose we cannot use integrals. Only derivatives

anonymous · Answer

I just guessed (:

anonymous · Answer

OK. Then
A=xy

for maximum area
dA/dx = 0

anonymous · Answer

attachment

anonymous · Answer

Cinar, how can you assume that the sides are all equal?

anonymous · Answer

Yes.  Maximum area of rectangle is when it is a square

anonymous · Answer

I don't get that. How is that possible?

anonymous · Answer

@QRAwarrior --> http://answers.yahoo.com/question/index?qid=20090410081125AAs5jCO

anonymous · Answer

yes, if you want to get max rectangle, it must be square..

anonymous · Answer

Ok cinar, because I don't have that much time (final is tomorrow), I'll take your word for it. Ok, so then its just merely solving for y = x*x? Because x and y are the same aren't they?

anonymous · Answer

y=x and not x*x. I think you meant area

anonymous · Answer

Should it not be:
(y-x)(y-x)?

anonymous · Answer

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