Question

help please

Solve 2 log x = log 64

x = 8
x = ±8
x = 32
x = 128

Answer 1

Raise both sides by then to get \(\LARGE 10^{2logx} = 64\). Remember exponentiation rules? 10^(ab) = (10^a)^b, so we get: \(\LARGE (10^{logx})^{2} = 64 -> x^2 = 64\)
Can you conclude from this?

Answer 2

ya i just wanted to double check my answer i got x=8 before thanks

Answer 3

No problem :-)