Ask your own question, for FREE!
Physics 19 Online
OpenStudy (anonymous):

It is NOT possible to completely convert A. heat into internal energy B. mechanical energy into heat C. internal energy into mechanical energy D. internal energy into heat

OpenStudy (experimentx):

C. internal energy into mechanical energy.

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

Can you explain . I think it should be all the 4options because effeciency can never be 100% for any energy related conversion process. Correct me if I am wrong @experimentX

OpenStudy (experimentx):

yeah .... thats correct.

OpenStudy (anonymous):

@experimentX , see this http://answers.yahoo.com/question/index?qid=20100307133158AAvFoUv

OpenStudy (anonymous):

@experimentX Looks like you are right :)

OpenStudy (anonymous):

Infact The answer should be A. The 2nd form of the 2nd law - heat cannot be completely converted into other forms of energy - places some practical restrictions on the efficiency of, for example, internal combustion and steam powered engines. Source: http://theory.uwinnipeg.ca/mod_tech/node80.html

OpenStudy (experimentx):

second law of thermodynamics ...

OpenStudy (anonymous):

Yes. I meant that :D

OpenStudy (anonymous):

Well it is A because heat can be converted but not completely as stated in the second law of thermodynamics. So A fits. You are right @shivam_bhalla

OpenStudy (anonymous):

@shivam_bhalla Isn't heat basically same as internal energy?

OpenStudy (experimentx):

during adiabatic process heat is converted to internal energy, dQ = dU + PdV

OpenStudy (mos1635):

adiabatic= no heat=>dQ=0 so dU=-PdV dU=-W

OpenStudy (experimentx):

sorry, it must have been ... isochoric process

OpenStudy (experimentx):

dV = 0

OpenStudy (anonymous):

@Aditya790 , http://en.wikipedia.org/wiki/Internal_energy

OpenStudy (anonymous):

@shivam_bhalla I've read the article you've mentioned. Internal energy is more of less the sum total of kinetic and potential energies of the constituent particles of the system. It is the total energy contained by the system. Heat is energy in transit and flows spontaneously from higher to lower temperature. It changes the potential and kinetic energy of the body it flows into, thereby changing its internal energy. So, heat transfer always causes change in internal energy of the system. Option A in incorrect as heat transfer causes a proportional increase in internal energy. That is, in fact, the statement of the first law of thermodynamics when no work is done. <<dU=dQ>> Option B is totally possible too, as in friction. Option C isn't possible. It would violate second law. Option D isn't possible as well since all of internal energy cannot be converted to heat. Heat transfer cannot take place with difference in temperature. To sum up, C and D are correct answers. I put considerable thought on this one and read enough upon the topic to tell you that they are indeed the correct answers.

OpenStudy (anonymous):

@Aditya790 ,According to me a)completely convert heat into internal energy--> not possible The 2nd form of the 2nd law - heat cannot be completely converted into other forms of energy In simple words it is the conversion of heat into other forms of energy that turns out never to be 100% efficient, even in principle Simple example would be the heat engine http://theory.uwinnipeg.ca/mod_tech/node80.html b)completely convert Mechanical energy to heat -->Possible -->Refer option D c) internal energy into mechanical energy-->Not certain mechanical energy = sum of potential energy and kinetic energy present in the components of a mechanical system internal energy = sum of all energies possessed by thermodynamic system essentially,They mean the same . Now If somebody can cite an example of such a conversion,then it would great. So not sure about this one D) internal energy into heat --->Possible Just read this statement, you will get your answer(read the Note) "The second law makes the very surprising statement that some of the heat energy must always be lost, so that the conversion from heat to work is never 100% efficient. Note, however, that this form of the 2nd law places no restriction on converting other forms of energy into heat - it is the conversion of heat into other forms of energy that turns out never to be 100% efficient, even in principle." So this is possible too So according to me the answer should be option A. I am not sure about option C

OpenStudy (ujjwal):

Ok my answer goes like this.. Give me an example of anything with internal energy=zero... If you can't believe the fact that internal energy can never be "completely" converted to any other forms of energy.. So, C and D is the correct answer according to me.. Regarding A and B, think of ideal conditions... stop thinking about heat engines.. they are not ideal.. In ideal conditions conversions mentioned in A and B are possible..

OpenStudy (anonymous):

Well, there is no mention to ideal conditions

OpenStudy (anonymous):

in the question

OpenStudy (ujjwal):

I know.. But you always suppose ideal conditions in physics.. Else even F=ma is incorrect..

OpenStudy (anonymous):

And I am saying that No energy can be converted into heat by 2nd law of thermodynamics

OpenStudy (anonymous):

I meant completely

OpenStudy (ujjwal):

give me the statement of second law of thermodynamics..

OpenStudy (anonymous):

Claussius statement No process is possible whose sole result is the transfer of heat from a body of lower temperature to a body of higher temperature

OpenStudy (anonymous):

Kelvin statement No process is possible in which the sole result is the absorption of heat from a reservoir and its complete conversion into work.

OpenStudy (ujjwal):

Claussius only talks about temperatures.. Not a problem.. Now regarding kelvin... where do you find reservoirs??

OpenStudy (anonymous):

The 2nd form of the 2nd law - heat cannot be completely converted into other forms of energy

OpenStudy (anonymous):

You asked for the statement of 2nd law of thermodynamics, so I just stated it. The one which is relevant to this context is stated above

OpenStudy (ujjwal):

Buddy, the statement of kelvin is made thinking about heat engines.. when you absorb heat from a reservoir and convert it into mechanical energy some energy is lost in sink.. But now think of one closed system.. and adiabatically expanding one. where internal energy (heat) is converted to mechanical energy..

OpenStudy (anonymous):

OK I agree to your point of view that kelvin's statement is made thinking of heat engines. In ideal context, your point of view appears right. :)

OpenStudy (anonymous):

What do you think about option C ?? I have no idea about it ?? What do you mean by internal energy to mechanical energy. Essentially they mean the same. Somebody can differentitiate them??

OpenStudy (ujjwal):

internal energy means sum of KE, vibrational energy, rotational energy and lots others.. you can't find exact value of internal energy but you can find the difference in internal energies of a body at two different set of conditions by just measuring the amount of energy released or absorbed when the body goes from one set of condition to other..

OpenStudy (anonymous):

OK. I got the answer myself. Sharing it for benefit of others Mechanical energy = KE + PE in mechanical system Internal Energy = KE + PE in thermodynamic system http://en.wikipedia.org/wiki/Mechanical_system http://en.wikipedia.org/wiki/Thermodynamic_system

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!