Question

Write an equation in slope intercept form of the line that passes through (4, 1) and (5, -1).

Answer 1

Equation:
\[\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}\]
Put (x1, y1) = (4, 1) and (x2, y2) = (5, -1)
\[\frac{y-1}{x-4} = \frac{-1-1}{5-4}\]
Can you continue from here?

Answer 2

deffiently not ...

Answer 3

Hmm.. Do you understand the above steps?

Answer 4

y = 4x + 3

Answer 5

Where does y = 4x + 3 come from? Can you show your workings?

Answer 6

Or please tell me which part you don't understand, so that I could explain it..

Answer 7

I was doing the wrong question on that last response . Lol Sorry.

Answer 8

Lol i don't understand any of it.. Im taking Higher classes than what im suppose to take ... So I just google all of my test and homework awnsers so i don't fail.. I do online ..

Answer 9

Then... perhaps you should learn it...

Answer 10

Basically, you need to find a slope first.
Slope = (y2 - y1)/(x2 - x1)
When (x1, y1) is the coordinates for a point. (x2, y2) is the coordinates for another point

Answer 11

Now in your case, let (x1, y1) = (4, 1) and (x2, y2) = (5, -1)
Can you put the values into the corresponding places? Show your workings please.

Answer 12

slope of a line is (y1-y2)/(x1-x2) for a line which passes through (x1,y1) and (x2,y2)...
slope int. form says
y = slope(x) + y int.
slope is -2
now y = -2x + y int.
now put y =1 and x =4 since the line passes thru (4,1) and hence the eqn. satisfies
it....putting the values we get y int. = 9
so eqn. is y = -2x + 9