Question

pls solve this problem for me!! ;)

Answer 1

Apparently, completing the square would be the best solution for this.

Answer 2

Why not the quadratic formula?

Answer 3

Well, the quadratic formula works, too, but then if you do this:
\[x^2-6x=-1\]
You'll see that the LHS is just a +9 away from being a perfect square.

Answer 4

x^2 -6x +1 =0
x_1,2=(6+/-sqrt(36-4))/2 =(6+/- sqrt(16*2))/2 =
=(6+/-4sqrt2)/2 =3+/-2sqrt2

Answer 5

We get the same answer for less work by doing this: (continuing from before)
\[x^2-6x+9=-1+9\\
(x-3)^2=8\\
x-3=\pm2\sqrt2\\
x=3\pm2\sqrt2\]

Answer 6

I think it is just what you are used to, I can pretty much write this one down directly from the quadratic formula in my head.
Which is not to say that completing the square is wrong, it's fine if you prefer that method and it works OK.