Question

t^2 + 10t + 26 =0

Answer 1

Use quadratic formula.

\[-b+-\sqrt { b^2-4ac \over 2a}\]

Answer 2

a= 1
b=10
c=26

Answer 3

Good job @order

Answer 4

t= \[-10 \pm \sqrt{-2}\]

t = \[-10 + i \sqrt{2}\]

Or t = \[-10 - i \sqrt{2}\]

Answer 5

What is this formula for @order ?

Answer 6

It's the same, but I forgot everyything has to go over 2a,

Answer 7

including the -b

Answer 8

no it's not the same b is seperate and has minus sign not over 2a

Answer 9

Ok, but the -b has to go over 2a, and I can't seem to write that in this equation stuffs... :(

Answer 10

No it doesn't have to go over 2a
the first formula you wrote before was perfect and right

Answer 11

I know what you mean

Answer 12

\[ x=\frac{-b \pm \sqrt {b^2-4ac}}{2a}, \]

Answer 13

Yes that's perfect!

Answer 14

yeah :D

Answer 15

Sorry I misunderstood you