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How to add fractions like these? \[\LARGE {2 \over x + 1} + {3 \over x + 2}\]
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you can cross multiply and get 3(x+1)=2(x+2)
oh like these okay so We have x+1 • 3 = 3x+3 x+2 • 2= 2x + 2 then just add that *like a boss*
not is right sure
Actually, 2(x + 2) = 2x + 4. reb
hahaha omg my bad...ooppsie
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Can you explain why?
why what?
Why they are cross multiplied?
2/(x+1) + 3/(x+2) =(2(x+2)+3(x+1))/(x+1)(x+2) = =(2x+4+3x+3)/(x+1)(x+2) =(5x+7)/(x+1)(x+2)
so because (x+1)(x+2) is the denominator common
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@jhonyy9 is absolutely correct
you can cross multiply to find x 3(x+1) 3x+3=3x/3=1 2(x+2) 2x+4=2x/2=2
Oh! I get it....
hope that this was understandably sure
You made me clear! Thanks!!!
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ok yw good luck bye
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