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Mathematics 7 Online
OpenStudy (anonymous):

Please find attached Question 21 (ii)

OpenStudy (anonymous):

It's upside down...

OpenStudy (anonymous):

OpenStudy (anonymous):

thanks

OpenStudy (ash2326):

@Hollywood_chrissy Confirm that \[(2x+1)^2+(2x^2+2x)^2=(2x^2+2x+1)^2\] Is this your question?

OpenStudy (ash2326):

@Hollywood_chrissy ???

OpenStudy (anonymous):

yes

OpenStudy (ash2326):

Take the right side \[(2x^2+2x+1)^2\] Let \[2x^2+2x=a\] so we have \[(2x^2+2x+1)^2=(a+1)^2=a^2+2a+1\] now substitute back \[a=2x^2+2x\] So, we get \[(2x^2+2x+1)^2=(2x^2+2x)^2+\underline{2(2x^2+2x)+1}\] See the underlined terms \[2(2x^2+2x)+1=4x^2+4x+1\] The right hand side is \[4x^2+4x+1=(2x)^2+2(2x)(1)+1=(2x+1)^2\] so we get \[(2x^2+2x+1)^2=(2x^2+2x)^2+(2x+1)^2\] Hence Proved

OpenStudy (ash2326):

@Hollywood_chrissy Do you understand this?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

do you mind lengthy methods which give correct answer.

OpenStudy (ash2326):

@Hollywood_chrissy What didn't you get? Sorry I was not here

OpenStudy (anonymous):

all of it.

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