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OpenStudy (anonymous):
It's upside down...
OpenStudy (anonymous):
OpenStudy (anonymous):
thanks
OpenStudy (ash2326):
@Hollywood_chrissy Confirm that
\[(2x+1)^2+(2x^2+2x)^2=(2x^2+2x+1)^2\]
Is this your question?
OpenStudy (ash2326):
@Hollywood_chrissy ???
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OpenStudy (anonymous):
yes
OpenStudy (ash2326):
Take the right side
\[(2x^2+2x+1)^2\]
Let \[2x^2+2x=a\]
so we have
\[(2x^2+2x+1)^2=(a+1)^2=a^2+2a+1\]
now substitute back
\[a=2x^2+2x\]
So, we get
\[(2x^2+2x+1)^2=(2x^2+2x)^2+\underline{2(2x^2+2x)+1}\]
See the underlined terms
\[2(2x^2+2x)+1=4x^2+4x+1\]
The right hand side is
\[4x^2+4x+1=(2x)^2+2(2x)(1)+1=(2x+1)^2\]
so we get
\[(2x^2+2x+1)^2=(2x^2+2x)^2+(2x+1)^2\]
Hence Proved
OpenStudy (ash2326):
@Hollywood_chrissy Do you understand this?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
do you mind lengthy methods which give correct answer.
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OpenStudy (ash2326):
@Hollywood_chrissy What didn't you get?
Sorry I was not here