If you were to use the substitution method to solve the following system, choose the new system of equations that would result if z was isolated in the first equation.

2x – 5y + z = 15
4x – y + 3z = 15
3x – 2y + 2z = 13

10x – 16y = –30
7x – 12y = –15

–2x + 14y = –30
–x + 8y = –17

22x + 16z = 90
11x + 8z = 43

–18x – 14z = –60
–5x + 8z = 43

If you were to use the substitution method to solve the following system, choose the new system of equations that would result if z was isolated in the first equation.

2x – 5y + z = 15
4x – y + 3z = 15
3x – 2y + 2z = 13

10x – 16y = –30
7x – 12y =

Question

If you were to use the substitution method to solve the following system, choose the new system of equations that would result if z was isolated in the first equation.

2x – 5y + z = 15
4x – y + 3z = 15
3x – 2y + 2z = 13

10x – 16y = –30
7x – 12y = –15
 
–2x + 14y = –30
–x + 8y = –17
 
22x + 16z = 90
11x + 8z = 43
 
–18x – 14z = –60
–5x + 8z = 43

If you were to use the substitution method to solve the following system, choose the new system of equations that would result if z was isolated in the first equation.

2x – 5y + z = 15
4x – y + 3z = 15
3x – 2y + 2z = 13

10x – 16y = –30
7x – 12y =

anonymous · Answer

Use eqn 1 therefore:$$z=15-2x+5y$$Then substitute into eqn 2:$$4x-y+3(15-2x+5y)=15$$$$4x-y+45-6x+15x=15$$$$-2x+14y=-30$$ and you can already see which solution it is.