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Gravel is being dumped from a conveyor belt at a rate of 10 cubic feet per minute. It forms a pile in the shape of a right circular cone whose base diameter and height are always equal to each other. How fast is the height of the pile increasing when the pile is 19 feet high? 1/3pi(r^2)(h) I've been getting V=1/3pih^3 V'=pih^2h' 10/(19^2*pi)=h' It's marking it wrong idk why...
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ahhh it says diameter.... lol
nvm
haha, you deserve a medal for that soultion! :D
thank you haha
0.705ft/sec is the answer h=d, v=(3.14*h^3)/12 differentiate both sides dv/dt=10,h=19,dh/dt=0.705
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