Question

If an object is dropped from a height of 144 feet,the function h(t)= - 16t^2 + 144 gives the height of the object after t seconds. When will the object hit the ground?

Answer 1

AT GROUND H=O
=-16T^2+144
T=SQRT(144/16)T

Answer 2

Since it hits the ground, h(t) =0 ( that is it is o the ground..)
h(t)= 0
- 16t^2 + 144 =0
Subtract both sides by 144, you'll get
-16t^2 = -144
Then, divide both sides by -16, you'll get
t^2 = 9
Now, take square root for both sides, what do you get?

Answer 3

its 3 s

Answer 4

Yes!~