Question

Identify the vertex and axis of symmetry f(x)= - 2x^2 + 2x-1

Answer 1

If you arrange it into f(x) = a(x-h)^2 +k
(h,k) is the coordinates of vertex and x=h is the axis of symmetry.
In your case,
f(x)= - 2x^2 + 2x-1
= -2 (x^2 -x) -1
= -2 ( x^2 -x +(1/2)^2 - (1/2)^2) -1
= -2 ( x- 1/2)^2 + 2(1/2)^2 -1
= -2 ( x- 1/2)^2 +1/2 -1
= -2 (x - 1/2)^2 -1/2
Can you get the answer from here?

Answer 2

I got 1/2 and -1/2

Answer 3

Complete the square,
- 2x^2 + 2x-1
-2(x^2-x)-1
\[-2(x-1/2)^2-1/2(-2)-1\]
\[-2(x-1/2)^2\]
Symmetry at x=1/2

Answer 4

wait

Answer 5

−2(x−1/2)2−1/4(−2)−1
= -2 (x - 1/2)^2 -1/2
symmetry at x=1/2

Answer 6

@dooley you're right for vertex

Answer 7

axis of symmetry is x=1/2
vertex is at (1/2, -1/2)

Answer 8

Thanks u guys!!1