What amount of hydrogen ions, in moles, is present in 100 L of wine: [H+ (aq)] = 1 x 10^-3 mol/L, seawater: pH=8.00, and stomach acid: [H+(aq)]=10.0 mol/L

Question

anonymous · Answer

amount of hydrogen ions in wine:
$$10^{-3} mol/L * 100L = 0.1 mol$$
amount of hydrogen ions in sea water :
$$P_H = 8 \rightarrow  -\log[H^+(aq)]= 8  \rightarrow  [H^+(aq)]= 10^{-8} $$ 
$$100L * 10^{-8} mlo/L = 10^{-6} mol $$
and the amount of hydrogen ions in stomach acid is :
$$100L*10mol/L = 1000mol$$