Question

integral (e^-2x) dx

Answer 1

(e^-2x)/(-2)

Answer 2

you should explain how you got that...

Answer 3

can someone show how to do it

Answer 4

there is nothing to explain... its simple formula based...

Answer 5

okay than tell me your simple formula

Answer 6

let u = -2x, so du/dx = -2 ---> du = -2dx ---> dx = -du/2


This means

int(e^(-2x)dx)


becomes


int(-1/2*e^u du)


-1/2*int(e^u du)


-1/2*(e^u+C)


-1/2*e^u+C


-1/2*e^(-2x)+C


So the answer is -1/2*e^(-2x)+C