Okay so can anyone give me a clear understanding of this? See the attachment.
its Stats and the question is about normal distribution.
Crazy question. My goodness.
Are you asking about 3? If so, you first need a z table.
It's the boxed one, right? Our first step is to look at the probability they gave us P(x> 5.2) = .9 find a z score that gives P = .9 That tells us how many standard deviations from the mean 5.2 is.
Find how many sigma above the mean gets you to 0.9
Below the mean, actually.
yes. then we use the info that mean= 2sigma so you know 5.2= 2s - as where a is from the z table.
Yeah, the idea is that you get 2 equations and 2 unknowns. One equation comes from your z-score info. The other equation comes from the mean being twice the SD.
You there, Hashsam1? Ask me questions.
and when we standardize X to Z. and plug 5.2-mean/sigma =a
why is a considered negative?
P(Z>a)=.9 ( and a is considered negative)
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