Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

Okay so can anyone give me a clear understanding of this? See the attachment.

OpenStudy (anonymous):

OpenStudy (anonymous):

its Stats and the question is about normal distribution.

OpenStudy (anonymous):

Crazy question. My goodness.

OpenStudy (phi):

Are you asking about 3? If so, you first need a z table.

OpenStudy (anonymous):

It's the boxed one, right? Our first step is to look at the probability they gave us P(x> 5.2) = .9 find a z score that gives P = .9 That tells us how many standard deviations from the mean 5.2 is.

OpenStudy (phi):

Find how many sigma above the mean gets you to 0.9

OpenStudy (anonymous):

Below the mean, actually.

OpenStudy (phi):

yes. then we use the info that mean= 2sigma so you know 5.2= 2s - as where a is from the z table.

OpenStudy (anonymous):

Yeah, the idea is that you get 2 equations and 2 unknowns. One equation comes from your z-score info. The other equation comes from the mean being twice the SD.

OpenStudy (anonymous):

You there, Hashsam1? Ask me questions.

OpenStudy (anonymous):

and when we standardize X to Z. and plug 5.2-mean/sigma =a

OpenStudy (anonymous):

why is a considered negative?

OpenStudy (anonymous):

P(Z>a)=.9 ( and a is considered negative)

OpenStudy (phi):

|dw:1335641014281:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!