Question

A coin is tossed three times, with 'heads' or 'tails' recorded after each toss. The number of possible outcomes for this event is

Answer 1

Eight possible outcomes. Each event has two possible outcomes, we're taking three events, so the answer is \[2^3=8\]

Answer 2

2^3=8

Answer 3

8

Answer 4

@lock5879, would you like an explanation?

Answer 5

thankyou guys.

Answer 6

& yes. please explain.

Answer 7

okay, think of this as a binary number.
there will be three digits, each digit having the possibilty of 1 or 0

Answer 8

0 = heads
1 = tails

you could have all heads = 000
you could have all tails = 111
if you play with the patterns, you can see that you will end up with eight total ways of filling out the three digits

Answer 9

If it helps, you can actually write out every possibility:
1. HHH
2. HHT
3. HTH
4. HTT
5. THH
6. THT
7. TTH
8. TTT