Question

Evaluate the indefinite integral of:

xlnx
-----
(x^2 - 1)^{1/2}

dx

Answer 1

I did a trig sub for the denominator, and got secA = x, tanA = (x^2-1)^{1/2}
But then, I ended up getting:



sec^2(A)*ln(secA)dA

Answer 2

I would rewrite that < i cant tell what your asking