Kyle has three short straws, four medium straws, and six long straws. If he randomly draws two straws, one at a time without replacement, what is the probability that both are short straws?
how many total straws?
That's what I'm trying to figure out myself.
wait 13 straws in all right?
very good.
on the first draw, what is the prob of getting a short one?
on the 2nd draw, remember that the number of short ones and the total number of straws have decreased by 1
3.846%. The first time he draws a stick, the chance of it being short is 3/13, but the second time the chance is 2/12, because no replacement. so the probability is them multiplied, so 6/156=1/26=3.846%.
on the first draw it is 3/13, which cannnot be reduced. on the 2nd draw it is 2/12=16 multiply the 2 togther and you get the prob of this outcome 3/13*(1/6)=3/78 or as wizguy said, 3.846%
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