Question

If \( y^3 = 16 x^2\), determine \(\frac{dx}{dt}\) when \( x = 4\) and \(\frac{dy}{dt} = -3 \) .

\(\frac{dx}{dt} = ?\)

Answer 1

sorry abt the format

Answer 2

i dont know how to make it in better format

Answer 3

Find \[\frac{dx}{dt}\ when\ \frac{dy}{dt}=-3\]

Answer 4

thanks

Answer 5

Differentiate y^3 = 16 x^2 with respect to t and plug in dy/dt.

Answer 6

@rukh did you understand ? Can you do it ?

Answer 7

Let\[y^3=16x^2.\]Then\[3y^2\cdot y'=32x\cdot x',\]\[3y^2\cdot (-3)=32(4)\cdot x',\]\[-9y^2=128x',\]\[x'=-\frac{9}{128}y^2.\]

Answer 8

ok thanks

Answer 9

@ ash2326 yes i can try...thank u

Answer 10

You're welcome but thank @across :D